So, the solution of the given pair of linear equations is x = 2, y = 5 II By Crossmultiplication method Let us write the given pair of linear equations is 8x 5y – 9 = 0 (3) 3x 2y – 4 = 0 (4) To solve the equations (3) and (4) by crossmultiplication method, we draw the diagram below Hence, the required solution of the given Transcript Example 7 Solve the following pair of equations by substitution method 7x – 15y = 2 x 2y = 3 7x – 15y = 2 x 2y = 3 From (1) 7x – 15y = 2 7x = 2 15y x = (𝟐 𝟏𝟓𝒚)/𝟕 Substituting the value of x in (2) x 2y = 3 (2 15𝑦)/7 2𝑦=3 Multiplying both sides by 7 7 × ((2 15𝑦)/7) 7×2𝑦=7×3 (2 15y) 14y = 21 15y 14y = 21 – 2 29y = 21 – 2Answer (1 of 10) Given system is (1/x) (1/y) = 7 (1) (2/x) (3/y) = 17 (2) For doing it by cross multiplication method there's an easy
Solve The System Of Equations By Using The Method Of Cross Multiplication 7x 2y 3 22x 3y 16 Sarthaks Econnect Largest Online Education Community
X 2y=3/2 2x y=3/2 by cross multiplication method
X 2y=3/2 2x y=3/2 by cross multiplication method- To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Solve `3xy2=0 , 2xy8=0` by method of cross multiplicationFree equations calculator solve linear, quadratic, polynomial, radical, exponential and logarithmic equations with all the steps Type in any equation to get the solution, steps and graph Solve, using crossmultiplication 5x 4y 14 = 0 3x =In case there is 2 =1/3 , b 1 /b 2 = 3/9 =1/3, c 1 /c 2 =3/2 = 3/2 ( 2) = (b 1 /b 2



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Examples on Cross Multiplication Method Example 1 Help Fredie to solve the following pair of linear equations by crossmultiplication 2x5y−52 = 0 3x−4y14 = 0 2 x 5 y − 52 = 0 3 x − 4 y 14 = 0 Solution The terms below x, negative y, and 1 are calculated below Thus, the solution isLogin Create Account Class9 » Maths Linear Equations in Two Variables Solve(cross multiplication method) 2/x3/y=2 1/x1/2y=1/3 Share with your friends Share 16 Dear student T a k i n g 1 x Solve for x and y by cross multiplication method asked in Important Questions by ajaykr Expert (106k points) 0 votes 1 answer Solve 4x 6/y =15 and 6x 8/y =14 by eliminating method and hence find p if y=px2 asked in Class X Maths by priya12 Expert (748k points) 0 votes 1 answer Using matrix method, solve the system of equations 3x 2y 2z = 3, x 2y
Solution Given simultaneous linear equations are 2x 5y = , x 2y = 4 On transposing, we get 2x 5y – = 0 —— (i) x 2y – 4 = 0 —— (ii x = 4, y = 1 WARNING!2xy−5 =03x2y−8 =0Using cross multiplication method, we getb1 c2 −b2 c1 x = c1 a2 −c2 a1 y = a1 b2 −a2 b1 1 2x = 1y = 11 So, x =2 and y = 1
Equation (1) can be written as 2x = 9 – 3y x = (9 – 3y)/ 2 (3) By substituting the value of x in equation (2) 3 × (9 – 3y)/ 2 4y = 5 By further calculation (27 – 9y)/ 2 4y = 5 By taking LCM Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions In case there is a unique solution, find it by using cross multiplication method (i) x – 3y – 3 = 0 3x – 9y – 2 = 0 (ii) 2x y = 5 3x 2y = 8 (iii) 3x – 5y = 6x – 10y = 40 (iv) x – 3y – 7 = 0 3x – 3y – 15 ⇒ 2(x y) = 4 – 3y ⇒ 2x 2y = 4 – 3y By further calculation 2x 2y 3y = 4 So we get 2x 5y = 4 (2) Now multiply equation (1) by 5 and (2) by 1 5x 5y = 30 ⇒ 2x 5y = 4 By subtracting both the equations 3x = 26 So we get x = 26/3 Substitute the value of x in (1) 26/3 y = 6 We can write it as y = 6 – 26/3 Taking LCM y = (18 – 26)/3 So we get y = – 8/3




Which Of The Following Pairs Of Linear Equations Has Unique Solution No Solution Or Infinitely Many Solution In Case There Is A Unique Solution Find It By Using Cross Multiplication Method Tex X 3y 3 0 Tex




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2x – 3 – 5 = 0 2x – 8 = 0 2x = 8 x = 8/2 x = 4 Therefore, the required solution is x = 4, y = 1 Example 4 Solve the system of linear equations 2x 5y = , x 2y = 4?To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Solve by cross multiplication `x2y1=0 `, `2x3y12=0` 2x y = 5 3x 2y = 8 As we can see that a 1 = 2, b 1 = 1 and c 1 = – 5 and a 2 = 3, b 2 = 2 and c 2 = – 8 ∴ Given pair of equations has unique solution By cross multiplication method, we have



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Solve The System Of Equations By Using The Method Of Cross Multiplication 7x 2y 3 22x 3y 16 Sarthaks Econnect Largest Online Education Community
Click here👆to get an answer to your question ️ Solve equartions by cross multiplication method 2x y = 6, x y = 2 Join / Login >> Class 10 >> Maths >> Pair of Linear Equations in Two Variables >> Algebraic Methods of Solving a Pair of Linear Equations >> Solve equartions by cross m Question Solve equartions by cross multiplication method 2 x − y = 6, x − y = 2 Easy OpenUse the method of substitution to answer this question Step 1 Rearrange one of the equations to find x or y yx=3 y=x3 Step 2 Substitute your y into the first equation x 2 2y=9 x 2 2(x3)=9 Step 3 Expand the brackets and rearrange to form a quadratic equation x 2 2x6=9 x 2 2x3=0 Step 4 Factorise the equation to find your values for x (x3)(x1)=0Therefore x=3 or x=1 Step Ex 35 ,1 Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions In case there is a unique solution, find it by using cross multiplication method (ii) 2x y = 5 3x 2y = 8 2x y = 5 3x 2y = 8 2x y = 5 2x 1y – 5 = 0 Comparing with a1x b1y c1 = 0 ∴ a1 = 2, b1 = 1, c1 = –5 3x 2y = 8 3x 2y – 8 = 0



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Solve The System Of Equations By Using The Method Of Cross Multiplication 7x 2y 3 0 11x 3 2 Y 8 0 Sarthaks Econnect Largest Online Education Community
Solve the following pair of linear equations by cross multiplication method 2x3y=13, yx=05 Updated On To keep watching this video solution for FREE, Download our App Join the 2 Crores Student community now!X/2 y = 6;5x – 1 = 3y asked in Linear Equations by Anika01 (Find the value of x and y using cross multiplication method 6x y = 18 and 5x 2y = 22 Ch1 Linear Equation In Two Variables X y/2=4 x/3 2y=5 by cross multiplication methodX/2 2y /3 = 1 and x – y/3 = 3 Solve the following pair of linear equations by the elimination method and the substitution method x y =5 and 2x –3y = 4 Substitution Method in Algebra!HELP PLZ!




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Which Of The Pairs Of Linear Equations Has Unique Solution No Solution
Solve the equations using the cross multiplication method 3x 2y = 10 and 4x − 2y = 4 Get the answer to this question and access other important questions, only at BYJU'SQuestion 2 x 2y z = 7, 2x y 2z = 4, x y 2z = 1 Solution Number of non zero rows are 3 ρ(A) = ρ(AB) = 3 The system is consistent and it has unique solution From the 1 st row, x2yz = 7 (1) From the 2 nd row, 5y = 10 (2) y = 2 From the 3 rd row,15z = 30 (3) z = 2 By applying the value of y and z in (1), we get x2(2)2 = 7 x6 = 7 x = 76 x = 1Label the two equations as the following x 2 2y = 9 y = x 3 Equation 2 can be substituted into equation 1, giving x 2 2( x 3 ) = 9Expanding the brackets and subtracting 9 from both sides means equation 1 becomes x 2 2x 3 = 0Then we can factorise this to create (x 3)(x 1) = 0Which means x = 3, and x = 1 Substituting these values into equation 2 gives usy = 0 and y




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